What are the solutions to the equation 3x^2+18x-48=0 ?

The solutions to the equation 3x^2+18x-48=0 are x=2,x=-8

Find the zeros of 3x^2+18x-48=0

The zeros of 3x^2+18x-48=0 are x=2,x=-8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} + 18 x - 48 = 0

x = 2, x = - 8

Solution steps

3 x^{2} + 18 x - 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 3 ( - 48 )}{2 \cdot 3}

1 8^{2} - 4 \cdot 3 (- 48) = 30

x_{1, 2} = \frac{- 18 \pm 30}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 18 + 30}{2 \cdot 3}, x_{2} = \frac{- 18 - 30}{2 \cdot 3}

x = \frac{- 18 + 30}{2 \cdot 3} : 2

x = \frac{- 18 - 30}{2 \cdot 3} : - 8

The solutions to the quadratic equation are:

x = 2, x = - 8

x, (x - 14)^{2} \cdot 1 0^{- 15} = 3

15 x^{2} + 2 x - 8 = 0

1 - 0.6 x - 0.27 x^{2} = 0

50 + t^{2} = 200 + 5 t

(x^{2}) (3) = 114

What are the solutions to the equation 3x^2+18x-48=0 ?
The solutions to the equation 3x^2+18x-48=0 are x=2,x=-8
Find the zeros of 3x^2+18x-48=0
The zeros of 3x^2+18x-48=0 are x=2,x=-8