What are the solutions to the equation -x^2+8x+12=0 ?

The solutions to the equation -x^2+8x+12=0 are x=-2(sqrt(7)-2),x=2(2+sqrt(7))

Find the zeros of -x^2+8x+12=0

The zeros of -x^2+8x+12=0 are x=-2(sqrt(7)-2),x=2(2+sqrt(7))

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- x^{2} + 8 x + 12 = 0

x = - 2 (7 - 2), x = 2 (2 + 7)

Decimal Notation

x = - 1.29150 \dots, x = 9.29150 \dots

Solution steps

- x^{2} + 8 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 1 ) \cdot 12}{2 ( - 1 )}

8^{2} - 4 (- 1) \cdot 12 = 47

x_{1, 2} = \frac{- 8 \pm 4 7}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 8 + 4 7}{2 ( - 1 )}, x_{2} = \frac{- 8 - 4 7}{2 ( - 1 )}

x = \frac{- 8 + 4 7}{2 ( - 1 )} : - 2 (7 - 2)

x = \frac{- 8 - 4 7}{2 ( - 1 )} : 2 (2 + 7)

The solutions to the quadratic equation are:

x = - 2 (7 - 2), x = 2 (2 + 7)

x^{2} + x + 3 = - 4

(x - 3)^{2} = 13

(- x + 2)^{2} = 3

(5 + x) (5 - x) = 7

- x^{2} - 3 x + 3

What are the solutions to the equation -x^2+8x+12=0 ?
The solutions to the equation -x^2+8x+12=0 are x=-2(sqrt(7)-2),x=2(2+sqrt(7))
Find the zeros of -x^2+8x+12=0
The zeros of -x^2+8x+12=0 are x=-2(sqrt(7)-2),x=2(2+sqrt(7))