What are the solutions to the equation (5+x)(5-x)=7 ?

The solutions to the equation (5+x)(5-x)=7 are x=-3sqrt(2),x=3sqrt(2)

Find the zeros of (5+x)(5-x)=7

The zeros of (5+x)(5-x)=7 are x=-3sqrt(2),x=3sqrt(2)

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(5 + x) (5 - x) = 7

x = - 32, x = 32

Decimal Notation

x = - 4.24264 \dots, x = 4.24264 \dots

Solution steps

(5 + x) (5 - x) = 7

Expand

(5 + x) (5 - x) : 25 - x^{2}

25 - x^{2} = 7

Move

7

to the left side

- x^{2} + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 ( - 1 ) \cdot 18}{2 ( - 1 )}

0^{2} - 4 (- 1) \cdot 18 = 62

x_{1, 2} = \frac{- 0 \pm 6 2}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 0 + 6 2}{2 ( - 1 )}, x_{2} = \frac{- 0 - 6 2}{2 ( - 1 )}

x = \frac{- 0 + 6 2}{2 ( - 1 )} : - 32

x = \frac{- 0 - 6 2}{2 ( - 1 )} : 32

The solutions to the quadratic equation are:

x = - 32, x = 32

- x^{2} - 3 x + 3

x^{2} + 4^{2} = 25

x^{2} - 4 x - 32 = 0

4 (x + 5)^{2} - 7 (x + 2)^{2} = 6 x

- 4 k^{2} - 8 k - 3 = - 3 - 5 k^{2}

What are the solutions to the equation (5+x)(5-x)=7 ?
The solutions to the equation (5+x)(5-x)=7 are x=-3sqrt(2),x=3sqrt(2)
Find the zeros of (5+x)(5-x)=7
The zeros of (5+x)(5-x)=7 are x=-3sqrt(2),x=3sqrt(2)