What are the solutions to the equation (-x+2)^2=3 ?

The solutions to the equation (-x+2)^2=3 are x=2-sqrt(3),x=2+sqrt(3)

Find the zeros of (-x+2)^2=3

The zeros of (-x+2)^2=3 are x=2-sqrt(3),x=2+sqrt(3)

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(- x + 2)^{2} = 3

x = 2 - 3, x = 2 + 3

Decimal Notation

x = 0.26794 \dots, x = 3.73205 \dots

Solution steps

(- x + 2)^{2} = 3

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

- x + 2 = 3 : x = 2 - 3

Solve

- x + 2 = - 3 : x = 2 + 3

The solutions to the quadratic equation are:

x = 2 - 3, x = 2 + 3

(5 + x) (5 - x) = 7

- x^{2} - 3 x + 3

x^{2} + 4^{2} = 25

x^{2} - 4 x - 32 = 0

4 (x + 5)^{2} - 7 (x + 2)^{2} = 6 x

What are the solutions to the equation (-x+2)^2=3 ?
The solutions to the equation (-x+2)^2=3 are x=2-sqrt(3),x=2+sqrt(3)
Find the zeros of (-x+2)^2=3
The zeros of (-x+2)^2=3 are x=2-sqrt(3),x=2+sqrt(3)