What are the solutions to the equation (-3-λ)(-4-λ)-(2)(1)=0 ?

The solutions to the equation (-3-λ)(-4-λ)-(2)(1)=0 are λ=-2,λ=-5

Find the zeros of (-3-λ)(-4-λ)-(2)(1)=0

The zeros of (-3-λ)(-4-λ)-(2)(1)=0 are λ=-2,λ=-5

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(- 3 - λ) (- 4 - λ) - (2) (1) = 0

λ = - 2, λ = - 5

Solution steps

(- 3 - λ) (- 4 - λ) - (2) (1) = 0

Expand

(- 3 - λ) (- 4 - λ) - (2) (1) : λ^{2} + 7 λ + 10

λ^{2} + 7 λ + 10 = 0

Solve with the quadratic formula

λ_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 10 = 3

λ_{1, 2} = \frac{- 7 \pm 3}{2 \cdot 1}

Separate the solutions

λ_{1} = \frac{- 7 + 3}{2 \cdot 1}, λ_{2} = \frac{- 7 - 3}{2 \cdot 1}

λ = \frac{- 7 + 3}{2 \cdot 1} : - 2

λ = \frac{- 7 - 3}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

λ = - 2, λ = - 5

2 x (x + 3) = - 1

x^{2} = - 25 (75 - 100)

n^{2} - 2 n - 7 = - 8

4 x^{2} - 56 x + 196 = 0

x, 4 x^{2} - 9 y^{2} = 2 x y^{2} + 3 x^{2} y - 1

What are the solutions to the equation (-3-λ)(-4-λ)-(2)(1)=0 ?
The solutions to the equation (-3-λ)(-4-λ)-(2)(1)=0 are λ=-2,λ=-5
Find the zeros of (-3-λ)(-4-λ)-(2)(1)=0
The zeros of (-3-λ)(-4-λ)-(2)(1)=0 are λ=-2,λ=-5