What are the solutions to the equation n^2-2n-7=-8 ?

The solutions to the equation n^2-2n-7=-8 are n=1

Find the zeros of n^2-2n-7=-8

The zeros of n^2-2n-7=-8 are n=1

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n^{2} - 2 n - 7 = - 8

n = 1

Solution steps

n^{2} - 2 n - 7 = - 8

Move

8

to the left side

n^{2} - 2 n + 1 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot 1 = 0

n_{1, 2} = \frac{- ( - 2 ) \pm 0}{2 \cdot 1}

n = \frac{- ( - 2 )}{2 \cdot 1}

\frac{- ( - 2 )}{2 \cdot 1} = 1

n = 1

The solution to the quadratic equation is:

n = 1

4 x^{2} - 56 x + 196 = 0

x, 4 x^{2} - 9 y^{2} = 2 x y^{2} + 3 x^{2} y - 1

x, y^{2} + x^{2} = r^{2}

\frac{7}{3} x + \frac{7}{3} = x^{2} + \frac{4}{3} x + \frac{1}{3}

8 x^{2} + 2 = 0

What are the solutions to the equation n^2-2n-7=-8 ?
The solutions to the equation n^2-2n-7=-8 are n=1
Find the zeros of n^2-2n-7=-8
The zeros of n^2-2n-7=-8 are n=1