What are the solutions to the equation (x+4)^2-36=0 ?

The solutions to the equation (x+4)^2-36=0 are x=2,x=-10

Find the zeros of (x+4)^2-36=0

The zeros of (x+4)^2-36=0 are x=2,x=-10

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(x + 4)^{2} - 36 = 0

x = 2, x = - 10

Solution steps

(x + 4)^{2} - 36 = 0

Move

36

to the right side

(x + 4)^{2} = 36

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 4 = 36 : x = 2

Solve

x + 4 = - 36 : x = - 10

The solutions to the quadratic equation are:

x = 2, x = - 10

x^{2} + 4 x + 2 = 0

8 x^{2} - 6 x^{2} = 54

300 = 500 - 2 x^{2}

2 (x^{2} + 7) = x^{2} + 10

x, \frac{y + 3}{2} x^{2} - (y + 2) x + \frac{y + 1}{2} = 0

What are the solutions to the equation (x+4)^2-36=0 ?
The solutions to the equation (x+4)^2-36=0 are x=2,x=-10
Find the zeros of (x+4)^2-36=0
The zeros of (x+4)^2-36=0 are x=2,x=-10