What are the solutions to the equation completesquare x^2+4x+2=0 ?

The solutions to the equation completesquare x^2+4x+2=0 are x=sqrt(2)-2,x=-sqrt(2)-2

Find the zeros of completesquare x^2+4x+2=0

The zeros of completesquare x^2+4x+2=0 are x=sqrt(2)-2,x=-sqrt(2)-2

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x^{2} + 4 x + 2 = 0

x = 2 - 2, x = - 2 - 2

Decimal Notation

x = - 0.58578 \dots, x = - 3.41421 \dots

Solution steps

x^{2} + 4 x + 2 = 0

Move

2

to the right side

x^{2} + 4 x = - 2

Rewrite in the form

(x + a)^{2} = b

(x + 2)^{2} = 2

For

the solutions are

f (x) = a, - a

Solve

x + 2 = 2 : x = 2 - 2

Solve

x + 2 = - 2 : x = - 2 - 2

The solutions to the quadratic equation are:

x = 2 - 2, x = - 2 - 2

8 x^{2} - 6 x^{2} = 54

300 = 500 - 2 x^{2}

2 (x^{2} + 7) = x^{2} + 10

x, \frac{y + 3}{2} x^{2} - (y + 2) x + \frac{y + 1}{2} = 0

1 - \frac{1}{6} x - \frac{1}{3} x^{2} = 0

What are the solutions to the equation completesquare x^2+4x+2=0 ?
The solutions to the equation completesquare x^2+4x+2=0 are x=sqrt(2)-2,x=-sqrt(2)-2
Find the zeros of completesquare x^2+4x+2=0
The zeros of completesquare x^2+4x+2=0 are x=sqrt(2)-2,x=-sqrt(2)-2