What are the solutions to the equation 2(x^2+7)=x^2+10 ?

The solutions to the equation 2(x^2+7)=x^2+10 are x=2i,x=-2i

Find the zeros of 2(x^2+7)=x^2+10

The zeros of 2(x^2+7)=x^2+10 are x=2i,x=-2i

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2 (x^{2} + 7) = x^{2} + 10

x = 2 i, x = - 2 i

Solution steps

2 (x^{2} + 7) = x^{2} + 10

Expand

2 (x^{2} + 7) : 2 x^{2} + 14

2 x^{2} + 14 = x^{2} + 10

Move

14

to the right side

2 x^{2} = x^{2} - 4

Move

x^{2}

to the left side

x^{2} = - 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 4, x = - - 4

- 4 = 2 i

- - 4 = - 2 i

x = 2 i, x = - 2 i

x, \frac{y + 3}{2} x^{2} - (y + 2) x + \frac{y + 1}{2} = 0

1 - \frac{1}{6} x - \frac{1}{3} x^{2} = 0

- 3 x^{2} + 14 x - 12 = 0

2 x^{2} + 2 x - 14 = 10

50 (z + 1)^{2} + 25 z = 121 - 41 (z - 1)^{2}

What are the solutions to the equation 2(x^2+7)=x^2+10 ?
The solutions to the equation 2(x^2+7)=x^2+10 are x=2i,x=-2i
Find the zeros of 2(x^2+7)=x^2+10
The zeros of 2(x^2+7)=x^2+10 are x=2i,x=-2i