What are the solutions to the equation x^2+x+9=20 ?

The solutions to the equation x^2+x+9=20 are x=(-1+3sqrt(5))/2 ,x=(-1-3sqrt(5))/2

Find the zeros of x^2+x+9=20

The zeros of x^2+x+9=20 are x=(-1+3sqrt(5))/2 ,x=(-1-3sqrt(5))/2

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x^{2} + x + 9 = 20

x = \frac{- 1 + 3 5}{2}, x = \frac{- 1 - 3 5}{2}

Decimal Notation

x = 2.85410 \dots, x = - 3.85410 \dots

Solution steps

x^{2} + x + 9 = 20

Move

20

to the left side

x^{2} + x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 11 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 11) = 35

x_{1, 2} = \frac{- 1 \pm 3 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 3 5}{2 \cdot 1}, x_{2} = \frac{- 1 - 3 5}{2 \cdot 1}

x = \frac{- 1 + 3 5}{2 \cdot 1} : \frac{- 1 + 3 5}{2}

x = \frac{- 1 - 3 5}{2 \cdot 1} : \frac{- 1 - 3 5}{2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 3 5}{2}, x = \frac{- 1 - 3 5}{2}

4 z^{2} + 2 z + 1 = 0

n^{2} - 5 n = - 4

x, 3 x^{2} - y^{2} = C

x^{2} + 14 x + 21 = 0

x, e^{f} = 1 + x^{2}

What are the solutions to the equation x^2+x+9=20 ?
The solutions to the equation x^2+x+9=20 are x=(-1+3sqrt(5))/2 ,x=(-1-3sqrt(5))/2
Find the zeros of x^2+x+9=20
The zeros of x^2+x+9=20 are x=(-1+3sqrt(5))/2 ,x=(-1-3sqrt(5))/2