What are the solutions to the equation (2y-1)(y-2)=0 ?

The solutions to the equation (2y-1)(y-2)=0 are y= 1/2 ,y=2

Find the zeros of (2y-1)(y-2)=0

The zeros of (2y-1)(y-2)=0 are y= 1/2 ,y=2

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(2 y - 1) (y - 2) = 0

y = \frac{1}{2}, y = 2

Decimal Notation

y = 0.5, y = 2

Solution steps

(2 y - 1) (y - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 y - 1 = 0 or y - 2 = 0

Solve

2 y - 1 = 0 : y = \frac{1}{2}

Solve

y - 2 = 0 : y = 2

The solutions to the quadratic equation are:

y = \frac{1}{2}, y = 2

- x^{2} - 7 x = - 18

x^{2} + 10 x + \frac{25}{2} = 0

t^{2} = 5 t - 6

2808.8 = 0.68 \cdot 2.14 \cdot 100 \cdot x \cdot (9.5 - 0.4 \cdot x)

2 x^{2} - 2 x + 3 = x^{2} - 3 x + 2

What are the solutions to the equation (2y-1)(y-2)=0 ?
The solutions to the equation (2y-1)(y-2)=0 are y= 1/2 ,y=2
Find the zeros of (2y-1)(y-2)=0
The zeros of (2y-1)(y-2)=0 are y= 1/2 ,y=2