What are the solutions to the equation p^2=4p ?

The solutions to the equation p^2=4p are p=4,p=0

Find the zeros of p^2=4p

The zeros of p^2=4p are p=4,p=0

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p^{2} = 4 p

p = 4, p = 0

Solution steps

p^{2} = 4 p

Move

4 p

to the left side

p^{2} - 4 p = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 0 = 4

p_{1, 2} = \frac{- ( - 4 ) \pm 4}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- ( - 4 ) + 4}{2 \cdot 1}, p_{2} = \frac{- ( - 4 ) - 4}{2 \cdot 1}

p = \frac{- ( - 4 ) + 4}{2 \cdot 1} : 4

p = \frac{- ( - 4 ) - 4}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

p = 4, p = 0

x^{2} - (m + 2) x + m + 1 = 0

24 x^{2} - 26 x + 5 = 0

x^{2} + x - a = 0

x^{2} + 6 x + 441 = 0

r^{2} + 40 r + 2000 = 0

What are the solutions to the equation p^2=4p ?
The solutions to the equation p^2=4p are p=4,p=0
Find the zeros of p^2=4p
The zeros of p^2=4p are p=4,p=0