What are the solutions to the equation solvefor x,x^2-3x-28=0 ?

The solutions to the equation solvefor x,x^2-3x-28=0 are x=7,x=-4

Find the zeros of solvefor x,x^2-3x-28=0

The zeros of solvefor x,x^2-3x-28=0 are x=7,x=-4

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x, x^{2} - 3 x - 28 = 0

x = 7, x = - 4

Solution steps

x^{2} - 3 x - 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 28 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 28) = 11

x_{1, 2} = \frac{- ( - 3 ) \pm 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 11}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 11}{2 \cdot 1}

x = \frac{- ( - 3 ) + 11}{2 \cdot 1} : 7

x = \frac{- ( - 3 ) - 11}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 7, x = - 4

6 x^{2} + 9 x = 0

x^{2} + 11 x - 242 = 0

a, c^{2} = a^{2} - b^{2}

p^{2} = 4 p

x^{2} - (m + 2) x + m + 1 = 0

What are the solutions to the equation solvefor x,x^2-3x-28=0 ?
The solutions to the equation solvefor x,x^2-3x-28=0 are x=7,x=-4
Find the zeros of solvefor x,x^2-3x-28=0
The zeros of solvefor x,x^2-3x-28=0 are x=7,x=-4