What are the solutions to the equation x^2-(m+2)x+m+1=0 ?

The solutions to the equation x^2-(m+2)x+m+1=0 are x=m+1,x=1

Find the zeros of x^2-(m+2)x+m+1=0

The zeros of x^2-(m+2)x+m+1=0 are x=m+1,x=1

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x^{2} - (m + 2) x + m + 1 = 0

x = m + 1, x = 1

Solution steps

x^{2} - (m + 2) x + m + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - m - 2 ) \pm ( - m - 2 ) ^{2} - 4 \cdot 1 \cdot ( m + 1 )}{2 \cdot 1}

Simplify

(- m - 2)^{2} - 4 \cdot 1 \cdot (m + 1) : m

x_{1, 2} = \frac{- ( - m - 2 ) \pm m}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - m - 2 ) + m}{2 \cdot 1}, x_{2} = \frac{- ( - m - 2 ) - m}{2 \cdot 1}

x = \frac{- ( - m - 2 ) + m}{2 \cdot 1} : m + 1

x = \frac{- ( - m - 2 ) - m}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = m + 1, x = 1

24 x^{2} - 26 x + 5 = 0

x^{2} + x - a = 0

x^{2} + 6 x + 441 = 0

r^{2} + 40 r + 2000 = 0

(y - 4)^{2} = (y - 4) (- y + 1)

What are the solutions to the equation x^2-(m+2)x+m+1=0 ?
The solutions to the equation x^2-(m+2)x+m+1=0 are x=m+1,x=1
Find the zeros of x^2-(m+2)x+m+1=0
The zeros of x^2-(m+2)x+m+1=0 are x=m+1,x=1