What are the solutions to the equation 24x^2-26x+5=0 ?

The solutions to the equation 24x^2-26x+5=0 are x= 5/6 ,x= 1/4

Find the zeros of 24x^2-26x+5=0

The zeros of 24x^2-26x+5=0 are x= 5/6 ,x= 1/4

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24 x^{2} - 26 x + 5 = 0

x = \frac{5}{6}, x = \frac{1}{4}

Decimal Notation

x = 0.83333 \dots, x = 0.25

Solution steps

24 x^{2} - 26 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 26 ) \pm ( - 26 ) ^{2} - 4 \cdot 24 \cdot 5}{2 \cdot 24}

(- 26)^{2} - 4 \cdot 24 \cdot 5 = 14

x_{1, 2} = \frac{- ( - 26 ) \pm 14}{2 \cdot 24}

Separate the solutions

x_{1} = \frac{- ( - 26 ) + 14}{2 \cdot 24}, x_{2} = \frac{- ( - 26 ) - 14}{2 \cdot 24}

x = \frac{- ( - 26 ) + 14}{2 \cdot 24} : \frac{5}{6}

x = \frac{- ( - 26 ) - 14}{2 \cdot 24} : \frac{1}{4}

The solutions to the quadratic equation are:

x = \frac{5}{6}, x = \frac{1}{4}

x^{2} + x - a = 0

x^{2} + 6 x + 441 = 0

r^{2} + 40 r + 2000 = 0

(y - 4)^{2} = (y - 4) (- y + 1)

2 x = x^{2} - 15

What are the solutions to the equation 24x^2-26x+5=0 ?
The solutions to the equation 24x^2-26x+5=0 are x= 5/6 ,x= 1/4
Find the zeros of 24x^2-26x+5=0
The zeros of 24x^2-26x+5=0 are x= 5/6 ,x= 1/4