What are the solutions to the equation x^2+x-a=0 ?

The solutions to the equation x^2+x-a=0 are x=(-1+sqrt(1+4a))/2 ,x=(-1-sqrt(1+4a))/2

Find the zeros of x^2+x-a=0

The zeros of x^2+x-a=0 are x=(-1+sqrt(1+4a))/2 ,x=(-1-sqrt(1+4a))/2

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x^{2} + x - a = 0

x = \frac{- 1 + 1 + 4 a}{2}, x = \frac{- 1 - 1 + 4 a}{2}

Solution steps

x^{2} + x - a = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - a )}{2 \cdot 1}

Simplify

1^{2} - 4 \cdot 1 \cdot (- a) : 1 + 4 a

x_{1, 2} = \frac{- 1 \pm 1 + 4 a}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 1 + 4 a}{2 \cdot 1}, x_{2} = \frac{- 1 - 1 + 4 a}{2 \cdot 1}

x = \frac{- 1 + 1 + 4 a}{2 \cdot 1} : \frac{- 1 + 1 + 4 a}{2}

x = \frac{- 1 - 1 + 4 a}{2 \cdot 1} : \frac{- 1 - 1 + 4 a}{2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 1 + 4 a}{2}, x = \frac{- 1 - 1 + 4 a}{2}

x^{2} + 6 x + 441 = 0

r^{2} + 40 r + 2000 = 0

(y - 4)^{2} = (y - 4) (- y + 1)

2 x = x^{2} - 15

z^{2} + 2 z^{2} + z - z + 9 = 0

What are the solutions to the equation x^2+x-a=0 ?
The solutions to the equation x^2+x-a=0 are x=(-1+sqrt(1+4a))/2 ,x=(-1-sqrt(1+4a))/2
Find the zeros of x^2+x-a=0
The zeros of x^2+x-a=0 are x=(-1+sqrt(1+4a))/2 ,x=(-1-sqrt(1+4a))/2