What are the solutions to the equation 3x^2-25x+42=0 ?

The solutions to the equation 3x^2-25x+42=0 are x=6,x= 7/3

Find the zeros of 3x^2-25x+42=0

The zeros of 3x^2-25x+42=0 are x=6,x= 7/3

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3 x^{2} - 25 x + 42 = 0

x = 6, x = \frac{7}{3}

Decimal Notation

x = 6, x = 2.33333 \dots

Solution steps

3 x^{2} - 25 x + 42 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 25 ) \pm ( - 25 ) ^{2} - 4 \cdot 3 \cdot 42}{2 \cdot 3}

(- 25)^{2} - 4 \cdot 3 \cdot 42 = 11

x_{1, 2} = \frac{- ( - 25 ) \pm 11}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 25 ) + 11}{2 \cdot 3}, x_{2} = \frac{- ( - 25 ) - 11}{2 \cdot 3}

x = \frac{- ( - 25 ) + 11}{2 \cdot 3} : 6

x = \frac{- ( - 25 ) - 11}{2 \cdot 3} : \frac{7}{3}

The solutions to the quadratic equation are:

x = 6, x = \frac{7}{3}

x, 2 p x^{2} + 6 x + 2 = 0

6 - x^{2} = 3 - 2 x

5 x^{2} + 6 x - 4 = 0

x, b^{2} x^{2} - a^{2} y^{2} = a^{2} b^{2}

1 0^{2} + x^{2} = 6^{2}

What are the solutions to the equation 3x^2-25x+42=0 ?
The solutions to the equation 3x^2-25x+42=0 are x=6,x= 7/3
Find the zeros of 3x^2-25x+42=0
The zeros of 3x^2-25x+42=0 are x=6,x= 7/3