What are the solutions to the equation 6-x^2=3-2x ?

The solutions to the equation 6-x^2=3-2x are x=-1,x=3

Find the zeros of 6-x^2=3-2x

The zeros of 6-x^2=3-2x are x=-1,x=3

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6 - x^{2} = 3 - 2 x

x = - 1, x = 3

Solution steps

6 - x^{2} = 3 - 2 x

Move

2 x

to the left side

6 - x^{2} + 2 x = 3

Move

3

to the left side

- x^{2} + 2 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 1 ) \cdot 3}{2 ( - 1 )}

2^{2} - 4 (- 1) \cdot 3 = 4

x_{1, 2} = \frac{- 2 \pm 4}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 2 + 4}{2 ( - 1 )}, x_{2} = \frac{- 2 - 4}{2 ( - 1 )}

x = \frac{- 2 + 4}{2 ( - 1 )} : - 1

x = \frac{- 2 - 4}{2 ( - 1 )} : 3

The solutions to the quadratic equation are:

x = - 1, x = 3

5 x^{2} + 6 x - 4 = 0

x, b^{2} x^{2} - a^{2} y^{2} = a^{2} b^{2}

1 0^{2} + x^{2} = 6^{2}

3 x (x - 2) - (x - 6) = 4 (x - 3) + 10

x, 2 x^{2} y = 0

What are the solutions to the equation 6-x^2=3-2x ?
The solutions to the equation 6-x^2=3-2x are x=-1,x=3
Find the zeros of 6-x^2=3-2x
The zeros of 6-x^2=3-2x are x=-1,x=3