What are the solutions to the equation 3x^2-96x+600=0 ?

The solutions to the equation 3x^2-96x+600=0 are x=2(8+sqrt(14)),x=2(8-sqrt(14))

Find the zeros of 3x^2-96x+600=0

The zeros of 3x^2-96x+600=0 are x=2(8+sqrt(14)),x=2(8-sqrt(14))

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3 x^{2} - 96 x + 600 = 0

x = 2 (8 + 14), x = 2 (8 - 14)

Decimal Notation

x = 23.48331 \dots, x = 8.51668 \dots

Solution steps

3 x^{2} - 96 x + 600 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 96 ) \pm ( - 96 ) ^{2} - 4 \cdot 3 \cdot 600}{2 \cdot 3}

(- 96)^{2} - 4 \cdot 3 \cdot 600 = 1214

x_{1, 2} = \frac{- ( - 96 ) \pm 12 14}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 96 ) + 12 14}{2 \cdot 3}, x_{2} = \frac{- ( - 96 ) - 12 14}{2 \cdot 3}

x = \frac{- ( - 96 ) + 12 14}{2 \cdot 3} : 2 (8 + 14)

x = \frac{- ( - 96 ) - 12 14}{2 \cdot 3} : 2 (8 - 14)

The solutions to the quadratic equation are:

x = 2 (8 + 14), x = 2 (8 - 14)

- 2 x^{2} - 8 x + 1 = 0

9 x^{2} - 7 = - 2

3 x^{2} - 24 x + 50 = 110000

x, z = 2 x^{2} + 2 y^{2}

6^{2} + x^{2} = 97

What are the solutions to the equation 3x^2-96x+600=0 ?
The solutions to the equation 3x^2-96x+600=0 are x=2(8+sqrt(14)),x=2(8-sqrt(14))
Find the zeros of 3x^2-96x+600=0
The zeros of 3x^2-96x+600=0 are x=2(8+sqrt(14)),x=2(8-sqrt(14))