What are the solutions to the equation 3x^2-24x+50=110000 ?

The solutions to the equation 3x^2-24x+50=110000 are x=4+3sqrt(4074),x=4-3sqrt(4074)

Find the zeros of 3x^2-24x+50=110000

The zeros of 3x^2-24x+50=110000 are x=4+3sqrt(4074),x=4-3sqrt(4074)

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3 x^{2} - 24 x + 50 = 110000

x = 4 + 34074, x = 4 - 34074

Decimal Notation

x = 195.48368 \dots, x = - 187.48368 \dots

Solution steps

3 x^{2} - 24 x + 50 = 110000

Move

110000

to the left side

3 x^{2} - 24 x - 109950 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 3 ( - 109950 )}{2 \cdot 3}

(- 24)^{2} - 4 \cdot 3 (- 109950) = 184074

x_{1, 2} = \frac{- ( - 24 ) \pm 18 4074}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 18 4074}{2 \cdot 3}, x_{2} = \frac{- ( - 24 ) - 18 4074}{2 \cdot 3}

x = \frac{- ( - 24 ) + 18 4074}{2 \cdot 3} : 4 + 34074

x = \frac{- ( - 24 ) - 18 4074}{2 \cdot 3} : 4 - 34074

The solutions to the quadratic equation are:

x = 4 + 34074, x = 4 - 34074

x, z = 2 x^{2} + 2 y^{2}

6^{2} + x^{2} = 97

6 x - 0.4 x^{2} = 3.12

6 x^{2} + 12 x + 2 = - 10

12 x = 9 x^{2} + 4

What are the solutions to the equation 3x^2-24x+50=110000 ?
The solutions to the equation 3x^2-24x+50=110000 are x=4+3sqrt(4074),x=4-3sqrt(4074)
Find the zeros of 3x^2-24x+50=110000
The zeros of 3x^2-24x+50=110000 are x=4+3sqrt(4074),x=4-3sqrt(4074)