What are the solutions to the equation 3x^2+42x+117=0 ?

The solutions to the equation 3x^2+42x+117=0 are x=-7+sqrt(10),x=-7-sqrt(10)

Find the zeros of 3x^2+42x+117=0

The zeros of 3x^2+42x+117=0 are x=-7+sqrt(10),x=-7-sqrt(10)

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3 x^{2} + 42 x + 117 = 0

x = - 7 + 10, x = - 7 - 10

Solution steps

3 x^{2} + 42 x + 117 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 42 \pm 4 2 ^{2} - 4 \cdot 3 \cdot 117}{2 \cdot 3}

4 2^{2} - 4 \cdot 3 \cdot 117 = 610

x_{1, 2} = \frac{- 42 \pm 6 10}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 42 + 6 10}{2 \cdot 3}, x_{2} = \frac{- 42 - 6 10}{2 \cdot 3}

x = \frac{- 42 + 6 10}{2 \cdot 3} : - 7 + 10

x = \frac{- 42 - 6 10}{2 \cdot 3} : - 7 - 10

The solutions to the quadratic equation are:

x = - 7 + 10, x = - 7 - 10

(3 x)^{2} = 324

x^{2} - x + \frac{1}{4}

3 x^{2} - 4 x = 20

x^{2} + 6 x = 79

2 t^{2} - 14 t + 3 = 3

What are the solutions to the equation 3x^2+42x+117=0 ?
The solutions to the equation 3x^2+42x+117=0 are x=-7+sqrt(10),x=-7-sqrt(10)
Find the zeros of 3x^2+42x+117=0
The zeros of 3x^2+42x+117=0 are x=-7+sqrt(10),x=-7-sqrt(10)