What are the solutions to the equation 3x^2-4x=20 ?

The solutions to the equation 3x^2-4x=20 are x= 10/3 ,x=-2

Find the zeros of 3x^2-4x=20

The zeros of 3x^2-4x=20 are x= 10/3 ,x=-2

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3 x^{2} - 4 x = 20

x = \frac{10}{3}, x = - 2

Decimal Notation

x = 3.33333 \dots, x = - 2

Solution steps

3 x^{2} - 4 x = 20

Move

20

to the left side

3 x^{2} - 4 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 3 ( - 20 )}{2 \cdot 3}

(- 4)^{2} - 4 \cdot 3 (- 20) = 16

x_{1, 2} = \frac{- ( - 4 ) \pm 16}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 16}{2 \cdot 3}, x_{2} = \frac{- ( - 4 ) - 16}{2 \cdot 3}

x = \frac{- ( - 4 ) + 16}{2 \cdot 3} : \frac{10}{3}

x = \frac{- ( - 4 ) - 16}{2 \cdot 3} : - 2

The solutions to the quadratic equation are:

x = \frac{10}{3}, x = - 2

x^{2} + 6 x = 79

2 t^{2} - 14 t + 3 = 3

- 8 t + 21 = - t^{2}

m^{4} - 13 m^{2} + 36

e^{- 3 x} + 7 \geq 15

What are the solutions to the equation 3x^2-4x=20 ?
The solutions to the equation 3x^2-4x=20 are x= 10/3 ,x=-2
Find the zeros of 3x^2-4x=20
The zeros of 3x^2-4x=20 are x= 10/3 ,x=-2