What are the solutions to the equation 3x^2-7x-5=1-2x^2 ?

The solutions to the equation 3x^2-7x-5=1-2x^2 are x=2,x=-3/5

Find the zeros of 3x^2-7x-5=1-2x^2

The zeros of 3x^2-7x-5=1-2x^2 are x=2,x=-3/5

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3 x^{2} - 7 x - 5 = 1 - 2 x^{2}

x = 2, x = - \frac{3}{5}

Decimal Notation

x = 2, x = - 0.6

Solution steps

3 x^{2} - 7 x - 5 = 1 - 2 x^{2}

Move

2 x^{2}

to the left side

5 x^{2} - 7 x - 5 = 1

Move

1

to the left side

5 x^{2} - 7 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 5 ( - 6 )}{2 \cdot 5}

(- 7)^{2} - 4 \cdot 5 (- 6) = 13

x_{1, 2} = \frac{- ( - 7 ) \pm 13}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 13}{2 \cdot 5}, x_{2} = \frac{- ( - 7 ) - 13}{2 \cdot 5}

x = \frac{- ( - 7 ) + 13}{2 \cdot 5} : 2

x = \frac{- ( - 7 ) - 13}{2 \cdot 5} : - \frac{3}{5}

The solutions to the quadratic equation are:

x = 2, x = - \frac{3}{5}

6 x^{2} - 5 x - 6 = 0

2 x^{2} - 18 x - 15 = 0

- x + x^{2} + 1 = 0

k, b (k d) (\frac{k d}{2}) = n A (d - k d)

x^{2} + 6 x + 19 = - 6

What are the solutions to the equation 3x^2-7x-5=1-2x^2 ?
The solutions to the equation 3x^2-7x-5=1-2x^2 are x=2,x=-3/5
Find the zeros of 3x^2-7x-5=1-2x^2
The zeros of 3x^2-7x-5=1-2x^2 are x=2,x=-3/5