What are the solutions to the equation -3x^2+17x=0 ?

The solutions to the equation -3x^2+17x=0 are x=0,x= 17/3

Find the zeros of -3x^2+17x=0

The zeros of -3x^2+17x=0 are x=0,x= 17/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 3 x^{2} + 17 x = 0

x = 0, x = \frac{17}{3}

Decimal Notation

x = 0, x = 5.66666 \dots

Solution steps

- 3 x^{2} + 17 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 ( - 3 ) \cdot 0}{2 ( - 3 )}

1 7^{2} - 4 (- 3) \cdot 0 = 17

x_{1, 2} = \frac{- 17 \pm 17}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 17 + 17}{2 ( - 3 )}, x_{2} = \frac{- 17 - 17}{2 ( - 3 )}

x = \frac{- 17 + 17}{2 ( - 3 )} : 0

x = \frac{- 17 - 17}{2 ( - 3 )} : \frac{17}{3}

The solutions to the quadratic equation are:

x = 0, x = \frac{17}{3}

x^{2} - (23 + 1) x + 23 = 0

3 x^{2} + 18 x - 9 = 0

\frac{m ^{2}}{5} - \frac{m}{2} = \frac{3}{10}

(x + 3) (x - 3) - (x - 2)^{2} = 6 + x (x - 5)

- 3 l^{2} + 20 l + 100 = 0

What are the solutions to the equation -3x^2+17x=0 ?
The solutions to the equation -3x^2+17x=0 are x=0,x= 17/3
Find the zeros of -3x^2+17x=0
The zeros of -3x^2+17x=0 are x=0,x= 17/3