What are the solutions to the equation x^2+25x+156=0 ?

The solutions to the equation x^2+25x+156=0 are x=-12,x=-13

Find the zeros of x^2+25x+156=0

The zeros of x^2+25x+156=0 are x=-12,x=-13

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x^{2} + 25 x + 156 = 0

x = - 12, x = - 13

Solution steps

x^{2} + 25 x + 156 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 25 \pm 2 5 ^{2} - 4 \cdot 1 \cdot 156}{2 \cdot 1}

2 5^{2} - 4 \cdot 1 \cdot 156 = 1

x_{1, 2} = \frac{- 25 \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 25 + 1}{2 \cdot 1}, x_{2} = \frac{- 25 - 1}{2 \cdot 1}

x = \frac{- 25 + 1}{2 \cdot 1} : - 12

x = \frac{- 25 - 1}{2 \cdot 1} : - 13

The solutions to the quadratic equation are:

x = - 12, x = - 13

p^{2} - 9 p = - 8

b^{2} - 13 b + 40 = 0

x, 3 x^{2} + 5 y^{2} - 12 x - 30 y + 60 = 0

x, f = x^{2} + 1 gx + 1

(x - 3) (x + 1) + 4 = 0

What are the solutions to the equation x^2+25x+156=0 ?
The solutions to the equation x^2+25x+156=0 are x=-12,x=-13
Find the zeros of x^2+25x+156=0
The zeros of x^2+25x+156=0 are x=-12,x=-13