What are the solutions to the equation x^2-x-a=0 ?

The solutions to the equation x^2-x-a=0 are x=(1+sqrt(1+4a))/2 ,x=(1-sqrt(1+4a))/2

Find the zeros of x^2-x-a=0

The zeros of x^2-x-a=0 are x=(1+sqrt(1+4a))/2 ,x=(1-sqrt(1+4a))/2

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x^{2} - x - a = 0

x = \frac{1 + 1 + 4 a}{2}, x = \frac{1 - 1 + 4 a}{2}

Solution steps

x^{2} - x - a = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - a )}{2 \cdot 1}

Simplify

(- 1)^{2} - 4 \cdot 1 \cdot (- a) : 1 + 4 a

x_{1, 2} = \frac{- ( - 1 ) \pm 1 + 4 a}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 1 + 4 a}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 1 + 4 a}{2 \cdot 1}

x = \frac{- ( - 1 ) + 1 + 4 a}{2 \cdot 1} : \frac{1 + 1 + 4 a}{2}

x = \frac{- ( - 1 ) - 1 + 4 a}{2 \cdot 1} : \frac{1 - 1 + 4 a}{2}

The solutions to the quadratic equation are:

x = \frac{1 + 1 + 4 a}{2}, x = \frac{1 - 1 + 4 a}{2}

(x + 1)^{2} = 4 x

- 6 x^{2} + 5 x - 1 = 0

64 r^{2} + 1 = 26

(3 x - 2)^{2} = 7

5 x^{2} + 6 = 6

What are the solutions to the equation x^2-x-a=0 ?
The solutions to the equation x^2-x-a=0 are x=(1+sqrt(1+4a))/2 ,x=(1-sqrt(1+4a))/2
Find the zeros of x^2-x-a=0
The zeros of x^2-x-a=0 are x=(1+sqrt(1+4a))/2 ,x=(1-sqrt(1+4a))/2