What are the solutions to the equation y^2-4y-3=0 ?

The solutions to the equation y^2-4y-3=0 are y=2+sqrt(7),y=2-sqrt(7)

Find the zeros of y^2-4y-3=0

The zeros of y^2-4y-3=0 are y=2+sqrt(7),y=2-sqrt(7)

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y^{2} - 4 y - 3 = 0

y = 2 + 7, y = 2 - 7

Decimal Notation

y = 4.64575 \dots, y = - 0.64575 \dots

Solution steps

y^{2} - 4 y - 3 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 3) = 27

y_{1, 2} = \frac{- ( - 4 ) \pm 2 7}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 4 ) + 2 7}{2 \cdot 1}, y_{2} = \frac{- ( - 4 ) - 2 7}{2 \cdot 1}

y = \frac{- ( - 4 ) + 2 7}{2 \cdot 1} : 2 + 7

y = \frac{- ( - 4 ) - 2 7}{2 \cdot 1} : 2 - 7

The solutions to the quadratic equation are:

y = 2 + 7, y = 2 - 7

3 a^{2} - 5 = 70

x^{2} + 8 x + 16 = 144

t, r (t) = 300 t - 300 t^{2}

1 7^{2} = x^{2} + (x + 7)^{2}

t, t^{2} + 12 t + a = 0

What are the solutions to the equation y^2-4y-3=0 ?
The solutions to the equation y^2-4y-3=0 are y=2+sqrt(7),y=2-sqrt(7)
Find the zeros of y^2-4y-3=0
The zeros of y^2-4y-3=0 are y=2+sqrt(7),y=2-sqrt(7)