What are the solutions to the equation (1/4 x+11)^2=147 ?

The solutions to the equation (1/4 x+11)^2=147 are x=28sqrt(3)-44,x=-28sqrt(3)-44

Find the zeros of (1/4 x+11)^2=147

The zeros of (1/4 x+11)^2=147 are x=28sqrt(3)-44,x=-28sqrt(3)-44

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(\frac{1}{4} x + 11)^{2} = 147

x = 283 - 44, x = - 283 - 44

Decimal Notation

x = 4.49742 \dots, x = - 92.49742 \dots

Solution steps

(\frac{1}{4} x + 11)^{2} = 147

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

\frac{1}{4} x + 11 = 147 : x = 283 - 44

Solve

\frac{1}{4} x + 11 = - 147 : x = - 283 - 44

The solutions to the quadratic equation are:

x = 283 - 44, x = - 283 - 44

x^{2} + 16 x + 56 = - 4 x

9 x^{2} - 21 x + 6 = 0

3 x^{2} = 20 x + 32

4 y^{2} + 5 = - 12 y

4 w^{2} - 20 w = 0

What are the solutions to the equation (1/4 x+11)^2=147 ?
The solutions to the equation (1/4 x+11)^2=147 are x=28sqrt(3)-44,x=-28sqrt(3)-44
Find the zeros of (1/4 x+11)^2=147
The zeros of (1/4 x+11)^2=147 are x=28sqrt(3)-44,x=-28sqrt(3)-44