What are the solutions to the equation x^2+16x+56=-4x ?

The solutions to the equation x^2+16x+56=-4x are x=2(sqrt(11)-5),x=-2(5+sqrt(11))

Find the zeros of x^2+16x+56=-4x

The zeros of x^2+16x+56=-4x are x=2(sqrt(11)-5),x=-2(5+sqrt(11))

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x^{2} + 16 x + 56 = - 4 x

x = 2 (11 - 5), x = - 2 (5 + 11)

Decimal Notation

x = - 3.36675 \dots, x = - 16.63324 \dots

Solution steps

x^{2} + 16 x + 56 = - 4 x

Move

4 x

to the left side

x^{2} + 20 x + 56 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot 56}{2 \cdot 1}

2 0^{2} - 4 \cdot 1 \cdot 56 = 411

x_{1, 2} = \frac{- 20 \pm 4 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 20 + 4 11}{2 \cdot 1}, x_{2} = \frac{- 20 - 4 11}{2 \cdot 1}

x = \frac{- 20 + 4 11}{2 \cdot 1} : 2 (11 - 5)

x = \frac{- 20 - 4 11}{2 \cdot 1} : - 2 (5 + 11)

The solutions to the quadratic equation are:

x = 2 (11 - 5), x = - 2 (5 + 11)

9 x^{2} - 21 x + 6 = 0

3 x^{2} = 20 x + 32

4 y^{2} + 5 = - 12 y

4 w^{2} - 20 w = 0

x^{2} + 22 x = - 85

What are the solutions to the equation x^2+16x+56=-4x ?
The solutions to the equation x^2+16x+56=-4x are x=2(sqrt(11)-5),x=-2(5+sqrt(11))
Find the zeros of x^2+16x+56=-4x
The zeros of x^2+16x+56=-4x are x=2(sqrt(11)-5),x=-2(5+sqrt(11))