What are the solutions to the equation -3x^2-10x+16=0 ?

The solutions to the equation -3x^2-10x+16=0 are x=-(5+sqrt(73))/3 ,x=(sqrt(73)-5)/3

Find the zeros of -3x^2-10x+16=0

The zeros of -3x^2-10x+16=0 are x=-(5+sqrt(73))/3 ,x=(sqrt(73)-5)/3

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- 3 x^{2} - 10 x + 16 = 0

x = - \frac{5 + 73}{3}, x = \frac{73 - 5}{3}

Decimal Notation

x = - 4.51466 \dots, x = 1.18133 \dots

Solution steps

- 3 x^{2} - 10 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 ( - 3 ) \cdot 16}{2 ( - 3 )}

(- 10)^{2} - 4 (- 3) \cdot 16 = 273

x_{1, 2} = \frac{- ( - 10 ) \pm 2 73}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 73}{2 ( - 3 )}, x_{2} = \frac{- ( - 10 ) - 2 73}{2 ( - 3 )}

x = \frac{- ( - 10 ) + 2 73}{2 ( - 3 )} : - \frac{5 + 73}{3}

x = \frac{- ( - 10 ) - 2 73}{2 ( - 3 )} : \frac{73 - 5}{3}

The solutions to the quadratic equation are:

x = - \frac{5 + 73}{3}, x = \frac{73 - 5}{3}

8 x^{2} + 22 x + 15 = 0

- 16 t^{2} + 10 t + 6 = 0

x, 9 x^{2} - 4 y^{2} + 36 x + 24 y = 0

2 x^{2} + 8 x + 4

x, x^{2} - y^{2} = a

What are the solutions to the equation -3x^2-10x+16=0 ?
The solutions to the equation -3x^2-10x+16=0 are x=-(5+sqrt(73))/3 ,x=(sqrt(73)-5)/3
Find the zeros of -3x^2-10x+16=0
The zeros of -3x^2-10x+16=0 are x=-(5+sqrt(73))/3 ,x=(sqrt(73)-5)/3