What are the solutions to the equation solvefor x,9x^2-4y^2+36x+24y=0 ?

The solutions to the equation solvefor x,9x^2-4y^2+36x+24y=0 are x=-(2y)/3 ,x=(2y-12)/3

Find the zeros of solvefor x,9x^2-4y^2+36x+24y=0

The zeros of solvefor x,9x^2-4y^2+36x+24y=0 are x=-(2y)/3 ,x=(2y-12)/3

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solve for

x, 9 x^{2} - 4 y^{2} + 36 x + 24 y = 0

x = - \frac{2 y}{3}, x = \frac{2 y - 12}{3}

Solution steps

9 x^{2} - 4 y^{2} + 36 x + 24 y = 0

Write in the standard form

a x^{2} + b x + c = 0

9 x^{2} + 36 x - 4 y^{2} + 24 y = 0

Factor

9 x^{2} + 36 x - 4 y^{2} + 24 y : (3 x + 2 y) (3 x - 2 y + 12)

(3 x + 2 y) (3 x - 2 y + 12) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x + 2 y = 0 or 3 x - 2 y + 12 = 0

Solve

3 x + 2 y = 0 : x = - \frac{2 y}{3}

Solve

3 x - 2 y + 12 = 0 : x = \frac{2 y - 12}{3}

The solutions to the quadratic equation are:

x = - \frac{2 y}{3}, x = \frac{2 y - 12}{3}

2 x^{2} + 8 x + 4

x, x^{2} - y^{2} = a

3 x^{2} + 12 x + 25 = 0

w^{2} + 10 w - 3 = 0

x, x^{2} + x - 5 = 0

What are the solutions to the equation solvefor x,9x^2-4y^2+36x+24y=0 ?
The solutions to the equation solvefor x,9x^2-4y^2+36x+24y=0 are x=-(2y)/3 ,x=(2y-12)/3
Find the zeros of solvefor x,9x^2-4y^2+36x+24y=0
The zeros of solvefor x,9x^2-4y^2+36x+24y=0 are x=-(2y)/3 ,x=(2y-12)/3