What are the solutions to the equation -5x^2+9x+3=0 ?

The solutions to the equation -5x^2+9x+3=0 are x=-(-9+sqrt(141))/(10),x=(9+sqrt(141))/(10)

Find the zeros of -5x^2+9x+3=0

The zeros of -5x^2+9x+3=0 are x=-(-9+sqrt(141))/(10),x=(9+sqrt(141))/(10)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 5 x^{2} + 9 x + 3 = 0

x = - \frac{- 9 + 141}{10}, x = \frac{9 + 141}{10}

Decimal Notation

x = - 0.28743 \dots, x = 2.08743 \dots

Solution steps

- 5 x^{2} + 9 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 ( - 5 ) \cdot 3}{2 ( - 5 )}

9^{2} - 4 (- 5) \cdot 3 = 141

x_{1, 2} = \frac{- 9 \pm 141}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 9 + 141}{2 ( - 5 )}, x_{2} = \frac{- 9 - 141}{2 ( - 5 )}

x = \frac{- 9 + 141}{2 ( - 5 )} : - \frac{- 9 + 141}{10}

x = \frac{- 9 - 141}{2 ( - 5 )} : \frac{9 + 141}{10}

The solutions to the quadratic equation are:

x = - \frac{- 9 + 141}{10}, x = \frac{9 + 141}{10}

- 6 + 8 x - x^{2} = 0

4 x (x - 5) = 0

a, (a + 2 d)^{2} = a^{2} + (a + d)^{2}

24 x^{2} + 128 x + 168 = 100 x^{2} + 40 x + 4

4 p^{2} - 78 = 11 p

What are the solutions to the equation -5x^2+9x+3=0 ?
The solutions to the equation -5x^2+9x+3=0 are x=-(-9+sqrt(141))/(10),x=(9+sqrt(141))/(10)
Find the zeros of -5x^2+9x+3=0
The zeros of -5x^2+9x+3=0 are x=-(-9+sqrt(141))/(10),x=(9+sqrt(141))/(10)