What are the solutions to the equation 2s^2+5s+6=0 ?

The solutions to the equation 2s^2+5s+6=0 are s=-5/4+i(sqrt(23))/4 ,s=-5/4-i(sqrt(23))/4

Find the zeros of 2s^2+5s+6=0

The zeros of 2s^2+5s+6=0 are s=-5/4+i(sqrt(23))/4 ,s=-5/4-i(sqrt(23))/4

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2 s^{2} + 5 s + 6 = 0

s = - \frac{5}{4} + i \frac{23}{4}, s = - \frac{5}{4} - i \frac{23}{4}

Solution steps

2 s^{2} + 5 s + 6 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 \cdot 6}{2 \cdot 2}

Simplify

5^{2} - 4 \cdot 2 \cdot 6 : 23 i

s_{1, 2} = \frac{- 5 \pm 23 i}{2 \cdot 2}

Separate the solutions

s_{1} = \frac{- 5 + 23 i}{2 \cdot 2}, s_{2} = \frac{- 5 - 23 i}{2 \cdot 2}

s = \frac{- 5 + 23 i}{2 \cdot 2} : - \frac{5}{4} + i \frac{23}{4}

s = \frac{- 5 - 23 i}{2 \cdot 2} : - \frac{5}{4} - i \frac{23}{4}

The solutions to the quadratic equation are:

s = - \frac{5}{4} + i \frac{23}{4}, s = - \frac{5}{4} - i \frac{23}{4}

- 5 x^{2} + 9 x + 3 = 0

- 6 + 8 x - x^{2} = 0

4 x (x - 5) = 0

a, (a + 2 d)^{2} = a^{2} + (a + d)^{2}

24 x^{2} + 128 x + 168 = 100 x^{2} + 40 x + 4

What are the solutions to the equation 2s^2+5s+6=0 ?
The solutions to the equation 2s^2+5s+6=0 are s=-5/4+i(sqrt(23))/4 ,s=-5/4-i(sqrt(23))/4
Find the zeros of 2s^2+5s+6=0
The zeros of 2s^2+5s+6=0 are s=-5/4+i(sqrt(23))/4 ,s=-5/4-i(sqrt(23))/4