What are the solutions to the equation 24x^2+128x+168=100x^2+40x+4 ?

The solutions to the equation 24x^2+128x+168=100x^2+40x+4 are x=-1,x= 41/19

Find the zeros of 24x^2+128x+168=100x^2+40x+4

The zeros of 24x^2+128x+168=100x^2+40x+4 are x=-1,x= 41/19

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24 x^{2} + 128 x + 168 = 100 x^{2} + 40 x + 4

x = - 1, x = \frac{41}{19}

Decimal Notation

x = - 1, x = 2.15789 \dots

Solution steps

24 x^{2} + 128 x + 168 = 100 x^{2} + 40 x + 4

Move

4

to the left side

24 x^{2} + 128 x + 164 = 100 x^{2} + 40 x

Move

40 x

to the left side

24 x^{2} + 88 x + 164 = 100 x^{2}

Move

100 x^{2}

to the left side

- 76 x^{2} + 88 x + 164 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 88 \pm 8 8 ^{2} - 4 ( - 76 ) \cdot 164}{2 ( - 76 )}

8 8^{2} - 4 (- 76) \cdot 164 = 240

x_{1, 2} = \frac{- 88 \pm 240}{2 ( - 76 )}

Separate the solutions

x_{1} = \frac{- 88 + 240}{2 ( - 76 )}, x_{2} = \frac{- 88 - 240}{2 ( - 76 )}

x = \frac{- 88 + 240}{2 ( - 76 )} : - 1

x = \frac{- 88 - 240}{2 ( - 76 )} : \frac{41}{19}

The solutions to the quadratic equation are:

x = - 1, x = \frac{41}{19}

4 p^{2} - 78 = 11 p

4 x^{2} - 5 x - 6 = 0

x, x y - x^{2} + e^{y} = 5

3 x^{2} - 25 x + 8 = 0

x^{2} - 24 = 120

What are the solutions to the equation 24x^2+128x+168=100x^2+40x+4 ?
The solutions to the equation 24x^2+128x+168=100x^2+40x+4 are x=-1,x= 41/19
Find the zeros of 24x^2+128x+168=100x^2+40x+4
The zeros of 24x^2+128x+168=100x^2+40x+4 are x=-1,x= 41/19