What are the solutions to the equation a^2-3a+3=3 ?

The solutions to the equation a^2-3a+3=3 are a=3,a=0

Find the zeros of a^2-3a+3=3

The zeros of a^2-3a+3=3 are a=3,a=0

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a^{2} - 3 a + 3 = 3

a = 3, a = 0

Solution steps

a^{2} - 3 a + 3 = 3

Move

3

to the left side

a^{2} - 3 a = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot 0 = 3

a_{1, 2} = \frac{- ( - 3 ) \pm 3}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 3 ) + 3}{2 \cdot 1}, a_{2} = \frac{- ( - 3 ) - 3}{2 \cdot 1}

a = \frac{- ( - 3 ) + 3}{2 \cdot 1} : 3

a = \frac{- ( - 3 ) - 3}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

a = 3, a = 0

2 v^{2} + v + 1 = 0

3 c^{2} - 13 c + 4 = - 4

y, x^{3} y^{2} = x^{2} + y^{2}

x^{2} + 2 x - 9 = 15

- 1 + \frac{( 60 - x ) ^{2}}{1200} = 0, x

What are the solutions to the equation a^2-3a+3=3 ?
The solutions to the equation a^2-3a+3=3 are a=3,a=0
Find the zeros of a^2-3a+3=3
The zeros of a^2-3a+3=3 are a=3,a=0