What are the solutions to the equation sqrt(38)^2+sqrt(26)^2=c^2 ?

The solutions to the equation sqrt(38)^2+sqrt(26)^2=c^2 are c=8,c=-8

Find the zeros of sqrt(38)^2+sqrt(26)^2=c^2

The zeros of sqrt(38)^2+sqrt(26)^2=c^2 are c=8,c=-8

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38^{2} + 26^{2} = c^{2}

c = 8, c = - 8

Solution steps

(38)^{2} + (26)^{2} = c^{2}

Switch sides

c^{2} = (38)^{2} + (26)^{2}

Simplify

(38)^{2} + (26)^{2} : 64

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 64, c = - 64

64 = 8

- 64 = - 8

c = 8, c = - 8

x, 3 x^{2} - 4 x + 3 = 0

2 x^{2} - 5 x - 2 = - 4 x + 1

x^{2} + 4 x = 1

2 x + 5 x^{2} = 1

(x + 3)^{2} = 3 (2 x + 3)

What are the solutions to the equation sqrt(38)^2+sqrt(26)^2=c^2 ?
The solutions to the equation sqrt(38)^2+sqrt(26)^2=c^2 are c=8,c=-8
Find the zeros of sqrt(38)^2+sqrt(26)^2=c^2
The zeros of sqrt(38)^2+sqrt(26)^2=c^2 are c=8,c=-8