What are the solutions to the equation 4x^2-35x+24=0 ?

The solutions to the equation 4x^2-35x+24=0 are x=8,x= 3/4

Find the zeros of 4x^2-35x+24=0

The zeros of 4x^2-35x+24=0 are x=8,x= 3/4

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4 x^{2} - 35 x + 24 = 0

x = 8, x = \frac{3}{4}

Decimal Notation

x = 8, x = 0.75

Solution steps

4 x^{2} - 35 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 35 ) \pm ( - 35 ) ^{2} - 4 \cdot 4 \cdot 24}{2 \cdot 4}

(- 35)^{2} - 4 \cdot 4 \cdot 24 = 29

x_{1, 2} = \frac{- ( - 35 ) \pm 29}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 35 ) + 29}{2 \cdot 4}, x_{2} = \frac{- ( - 35 ) - 29}{2 \cdot 4}

x = \frac{- ( - 35 ) + 29}{2 \cdot 4} : 8

x = \frac{- ( - 35 ) - 29}{2 \cdot 4} : \frac{3}{4}

The solutions to the quadratic equation are:

x = 8, x = \frac{3}{4}

ω, \frac{π}{4} \cdot 2 0^{2} \cdot 50 = \frac{π}{4} ω^{2} \cdot 60

- 2 x = 5 + 2 x + 3 x^{2}

28090 = 25000 (1 + \frac{r}{100})^{2}

(x + 4)^{2} = 361

3 x^{2} + 5 = 16 x

What are the solutions to the equation 4x^2-35x+24=0 ?
The solutions to the equation 4x^2-35x+24=0 are x=8,x= 3/4
Find the zeros of 4x^2-35x+24=0
The zeros of 4x^2-35x+24=0 are x=8,x= 3/4