What are the solutions to the equation 2x^2+3x+20=0 ?

The solutions to the equation 2x^2+3x+20=0 are x=-3/4+i(sqrt(151))/4 ,x=-3/4-i(sqrt(151))/4

Find the zeros of 2x^2+3x+20=0

The zeros of 2x^2+3x+20=0 are x=-3/4+i(sqrt(151))/4 ,x=-3/4-i(sqrt(151))/4

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2 x^{2} + 3 x + 20 = 0

x = - \frac{3}{4} + i \frac{151}{4}, x = - \frac{3}{4} - i \frac{151}{4}

Solution steps

2 x^{2} + 3 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 2 \cdot 20}{2 \cdot 2}

Simplify

3^{2} - 4 \cdot 2 \cdot 20 : 151 i

x_{1, 2} = \frac{- 3 \pm 151 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 3 + 151 i}{2 \cdot 2}, x_{2} = \frac{- 3 - 151 i}{2 \cdot 2}

x = \frac{- 3 + 151 i}{2 \cdot 2} : - \frac{3}{4} + i \frac{151}{4}

x = \frac{- 3 - 151 i}{2 \cdot 2} : - \frac{3}{4} - i \frac{151}{4}

The solutions to the quadratic equation are:

x = - \frac{3}{4} + i \frac{151}{4}, x = - \frac{3}{4} - i \frac{151}{4}

4 x^{2} + 5 = 33

x (x - 1) = (3 x + 1) (x + 2) + 4

x, f = p x^{2} - 4

2 x^{2} - 10 x + 15 = 0

x^{2} + 6 x - 7 = 0

What are the solutions to the equation 2x^2+3x+20=0 ?
The solutions to the equation 2x^2+3x+20=0 are x=-3/4+i(sqrt(151))/4 ,x=-3/4-i(sqrt(151))/4
Find the zeros of 2x^2+3x+20=0
The zeros of 2x^2+3x+20=0 are x=-3/4+i(sqrt(151))/4 ,x=-3/4-i(sqrt(151))/4