What are the solutions to the equation x^2-4ax-b^2+4a^2=0 ?

The solutions to the equation x^2-4ax-b^2+4a^2=0 are x=2a+b,x=2a-b

Find the zeros of x^2-4ax-b^2+4a^2=0

The zeros of x^2-4ax-b^2+4a^2=0 are x=2a+b,x=2a-b

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x^{2} - 4 a x - b^{2} + 4 a^{2} = 0

x = 2 a + b, x = 2 a - b

Solution steps

x^{2} - 4 a x - b^{2} + 4 a^{2} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 a ) \pm ( - 4 a ) ^{2} - 4 \cdot 1 \cdot ( - b ^{2} + 4 a ^{2} )}{2 \cdot 1}

Simplify

(- 4 a)^{2} - 4 \cdot 1 \cdot (- b^{2} + 4 a^{2}) : 2 b

x_{1, 2} = \frac{- ( - 4 a ) \pm 2 b}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 a ) + 2 b}{2 \cdot 1}, x_{2} = \frac{- ( - 4 a ) - 2 b}{2 \cdot 1}

x = \frac{- ( - 4 a ) + 2 b}{2 \cdot 1} : 2 a + b

x = \frac{- ( - 4 a ) - 2 b}{2 \cdot 1} : 2 a - b

The solutions to the quadratic equation are:

x = 2 a + b, x = 2 a - b

(6 - x) (3 - x) - 4 = 0

(\frac{1}{3}) \cdot x^{2} + 3 = 0

(3 x - 8)^{2} = - 50

x^{2} + 1 2^{2} = 1 6^{2}

z^{2} + 2 z + 17 = 0

What are the solutions to the equation x^2-4ax-b^2+4a^2=0 ?
The solutions to the equation x^2-4ax-b^2+4a^2=0 are x=2a+b,x=2a-b
Find the zeros of x^2-4ax-b^2+4a^2=0
The zeros of x^2-4ax-b^2+4a^2=0 are x=2a+b,x=2a-b