What are the solutions to the equation -0.01x^2+3.6x-180=0 ?

The solutions to the equation -0.01x^2+3.6x-180=0 are x=60,x=300

Find the zeros of -0.01x^2+3.6x-180=0

The zeros of -0.01x^2+3.6x-180=0 are x=60,x=300

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- 0.01 x^{2} + 3.6 x - 180 = 0

x = 60, x = 300

Solution steps

- 0.01 x^{2} + 3.6 x - 180 = 0

Multiply both sides by

100

- x^{2} + 360 x - 18000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 360 \pm 36 0 ^{2} - 4 ( - 1 ) ( - 18000 )}{2 ( - 1 )}

36 0^{2} - 4 (- 1) (- 18000) = 240

x_{1, 2} = \frac{- 360 \pm 240}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 360 + 240}{2 ( - 1 )}, x_{2} = \frac{- 360 - 240}{2 ( - 1 )}

x = \frac{- 360 + 240}{2 ( - 1 )} : 60

x = \frac{- 360 - 240}{2 ( - 1 )} : 300

The solutions to the quadratic equation are:

x = 60, x = 300

2 x (2 x - 1) - x^{2} + x = 0

x^{2} - 2 x - \frac{x}{2} = 0

\frac{1}{20} x^{2} + 3 x + 50 = 0

(x - 3) (2 x - 1) + (x - 3) (- x + 5) = 0

3 \cdot (x + 2) \cdot (x - 2) = (x - 4)^{2} + 8 x

What are the solutions to the equation -0.01x^2+3.6x-180=0 ?
The solutions to the equation -0.01x^2+3.6x-180=0 are x=60,x=300
Find the zeros of -0.01x^2+3.6x-180=0
The zeros of -0.01x^2+3.6x-180=0 are x=60,x=300