What are the solutions to the equation L^2-10L+24=0 ?

The solutions to the equation L^2-10L+24=0 are L=6,L=4

Find the zeros of L^2-10L+24=0

The zeros of L^2-10L+24=0 are L=6,L=4

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L^{2} - 10 L + 24 = 0

L = 6, L = 4

Solution steps

L^{2} - 10 L + 24 = 0

Solve with the quadratic formula

L_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 24 = 2

L_{1, 2} = \frac{- ( - 10 ) \pm 2}{2 \cdot 1}

Separate the solutions

L_{1} = \frac{- ( - 10 ) + 2}{2 \cdot 1}, L_{2} = \frac{- ( - 10 ) - 2}{2 \cdot 1}

L = \frac{- ( - 10 ) + 2}{2 \cdot 1} : 6

L = \frac{- ( - 10 ) - 2}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

L = 6, L = 4

0.15 c^{2} + 4.86072 c - 2.5284 = 0

x^{2} + 0.1 x + 4 = 0

x^{2} - 300 x + 14400 = 0

9 x^{2} + 24 x + 20 = 4

(x^{2} - 25) = 0

What are the solutions to the equation L^2-10L+24=0 ?
The solutions to the equation L^2-10L+24=0 are L=6,L=4
Find the zeros of L^2-10L+24=0
The zeros of L^2-10L+24=0 are L=6,L=4