What are the solutions to the equation x^2+0.1x+4=0 ?

The solutions to the equation x^2+0.1x+4=0 are x=-1/20+i(sqrt(1599))/(20),x=-1/20-i(sqrt(1599))/(20)

Find the zeros of x^2+0.1x+4=0

The zeros of x^2+0.1x+4=0 are x=-1/20+i(sqrt(1599))/(20),x=-1/20-i(sqrt(1599))/(20)

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x^{2} + 0.1 x + 4 = 0

x = - \frac{1}{20} + i \frac{1599}{20}, x = - \frac{1}{20} - i \frac{1599}{20}

Solution steps

x^{2} + 0.1 x + 4 = 0

Multiply both sides by

10

10 x^{2} + x + 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 10 \cdot 40}{2 \cdot 10}

Simplify

1^{2} - 4 \cdot 10 \cdot 40 : 1599 i

x_{1, 2} = \frac{- 1 \pm 1599 i}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 1 + 1599 i}{2 \cdot 10}, x_{2} = \frac{- 1 - 1599 i}{2 \cdot 10}

x = \frac{- 1 + 1599 i}{2 \cdot 10} : - \frac{1}{20} + i \frac{1599}{20}

x = \frac{- 1 - 1599 i}{2 \cdot 10} : - \frac{1}{20} - i \frac{1599}{20}

The solutions to the quadratic equation are:

x = - \frac{1}{20} + i \frac{1599}{20}, x = - \frac{1}{20} - i \frac{1599}{20}

x^{2} - 300 x + 14400 = 0

9 x^{2} + 24 x + 20 = 4

(x^{2} - 25) = 0

x^{2} + 6 x + 11 = 3

y^{2} - 3 y + 10 = 0

What are the solutions to the equation x^2+0.1x+4=0 ?
The solutions to the equation x^2+0.1x+4=0 are x=-1/20+i(sqrt(1599))/(20),x=-1/20-i(sqrt(1599))/(20)
Find the zeros of x^2+0.1x+4=0
The zeros of x^2+0.1x+4=0 are x=-1/20+i(sqrt(1599))/(20),x=-1/20-i(sqrt(1599))/(20)