What are the solutions to the equation s^2-36+0s=0 ?

The solutions to the equation s^2-36+0s=0 are s=6,s=-6

Find the zeros of s^2-36+0s=0

The zeros of s^2-36+0s=0 are s=6,s=-6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

s^{2} - 36 + 0 s = 0

s = 6, s = - 6

Solution steps

s^{2} - 36 + 0 \cdot s = 0

Refine

s^{2} - 36 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 1 \cdot ( - 36 )}{2 \cdot 1}

0^{2} - 4 \cdot 1 \cdot (- 36) = 12

s_{1, 2} = \frac{- 0 \pm 12}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 0 + 12}{2 \cdot 1}, s_{2} = \frac{- 0 - 12}{2 \cdot 1}

s = \frac{- 0 + 12}{2 \cdot 1} : 6

s = \frac{- 0 - 12}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

s = 6, s = - 6

4 z^{2} - 8 z = 0

2 x^{2} + 32 x = 0

3 s^{2} + 16 s + 12 = 0

5 (4 x - 3)^{2} - 4 (x - 9) (3 x + 5) = 9

x, x^{2} + y^{2} + z^{2} - 4 x + 6 y - 8 z = - 20

What are the solutions to the equation s^2-36+0s=0 ?
The solutions to the equation s^2-36+0s=0 are s=6,s=-6
Find the zeros of s^2-36+0s=0
The zeros of s^2-36+0s=0 are s=6,s=-6