What are the solutions to the equation 12x^2-10x+1=7 ?

The solutions to the equation 12x^2-10x+1=7 are x=(5+sqrt(97))/(12),x=(5-sqrt(97))/(12)

Find the zeros of 12x^2-10x+1=7

The zeros of 12x^2-10x+1=7 are x=(5+sqrt(97))/(12),x=(5-sqrt(97))/(12)

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12 x^{2} - 10 x + 1 = 7

x = \frac{5 + 97}{12}, x = \frac{5 - 97}{12}

Decimal Notation

x = 1.23740 \dots, x = - 0.40407 \dots

Solution steps

12 x^{2} - 10 x + 1 = 7

Move

7

to the left side

12 x^{2} - 10 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 12 ( - 6 )}{2 \cdot 12}

(- 10)^{2} - 4 \cdot 12 (- 6) = 297

x_{1, 2} = \frac{- ( - 10 ) \pm 2 97}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 97}{2 \cdot 12}, x_{2} = \frac{- ( - 10 ) - 2 97}{2 \cdot 12}

x = \frac{- ( - 10 ) + 2 97}{2 \cdot 12} : \frac{5 + 97}{12}

x = \frac{- ( - 10 ) - 2 97}{2 \cdot 12} : \frac{5 - 97}{12}

The solutions to the quadratic equation are:

x = \frac{5 + 97}{12}, x = \frac{5 - 97}{12}

900 x^{2} = 9

4 x^{2} = - 12 x

x, x^{2} + 2 y^{2} + 3 z^{2} = 6

x^{1 + l o g_{x} (36)} = 6 x^{2}

x, x^{2} - \frac{23}{3} x + 14 = 0

What are the solutions to the equation 12x^2-10x+1=7 ?
The solutions to the equation 12x^2-10x+1=7 are x=(5+sqrt(97))/(12),x=(5-sqrt(97))/(12)
Find the zeros of 12x^2-10x+1=7
The zeros of 12x^2-10x+1=7 are x=(5+sqrt(97))/(12),x=(5-sqrt(97))/(12)