What are the solutions to the equation 2λ^2-1=0 ?

The solutions to the equation 2λ^2-1=0 are λ= 1/(sqrt(2)),λ=-1/(sqrt(2))

Find the zeros of 2λ^2-1=0

The zeros of 2λ^2-1=0 are λ= 1/(sqrt(2)),λ=-1/(sqrt(2))

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2 λ^{2} - 1 = 0

λ = \frac{1}{2}, λ = - \frac{1}{2}

Decimal Notation

λ = 0.70710 \dots, λ = - 0.70710 \dots

Solution steps

2 λ^{2} - 1 = 0

Move

1

to the right side

2 λ^{2} = 1

Divide both sides by

2

λ^{2} = \frac{1}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

λ = \frac{1}{2}, λ = - \frac{1}{2}

\frac{1}{2} = \frac{1}{2}

- \frac{1}{2} = - \frac{1}{2}

λ = \frac{1}{2}, λ = - \frac{1}{2}

x, z = 1 + (x - 1)^{2} + 4 y^{2}

m^{2} - 5 m - 14 = 0

- 10000 x^{2} + 4000 x + 9000 = 0

6 + 4 (4.5 - x) = 4 + x^{2}

2 x (2 x - 3) = 6 + x

What are the solutions to the equation 2λ^2-1=0 ?
The solutions to the equation 2λ^2-1=0 are λ= 1/(sqrt(2)),λ=-1/(sqrt(2))
Find the zeros of 2λ^2-1=0
The zeros of 2λ^2-1=0 are λ= 1/(sqrt(2)),λ=-1/(sqrt(2))