What are the solutions to the equation solvefor x,z=1+(x-1)^2+4y^2 ?

The solutions to the equation solvefor x,z=1+(x-1)^2+4y^2 are x=sqrt(z-4y^2-1)+1,x=-sqrt(z-4y^2-1)+1

Find the zeros of solvefor x,z=1+(x-1)^2+4y^2

The zeros of solvefor x,z=1+(x-1)^2+4y^2 are x=sqrt(z-4y^2-1)+1,x=-sqrt(z-4y^2-1)+1

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solve for

x, z = 1 + (x - 1)^{2} + 4 y^{2}

x = z - 4 y^{2} - 1 + 1, x = - z - 4 y^{2} - 1 + 1

Solution steps

z = 1 + (x - 1)^{2} + 4 y^{2}

Switch sides

1 + (x - 1)^{2} + 4 y^{2} = z

Move

4 y^{2}

to the right side

1 + (x - 1)^{2} = z - 4 y^{2}

Move

1

to the right side

(x - 1)^{2} = z - 4 y^{2} - 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = z - 4 y^{2} - 1 : x = z - 4 y^{2} - 1 + 1

Solve

x - 1 = - z - 4 y^{2} - 1 : x = - z - 4 y^{2} - 1 + 1

The solutions to the quadratic equation are:

x = z - 4 y^{2} - 1 + 1, x = - z - 4 y^{2} - 1 + 1

m^{2} - 5 m - 14 = 0

- 10000 x^{2} + 4000 x + 9000 = 0

6 + 4 (4.5 - x) = 4 + x^{2}

2 x (2 x - 3) = 6 + x

13 x^{2} - 17 x + 7 = 0

What are the solutions to the equation solvefor x,z=1+(x-1)^2+4y^2 ?
The solutions to the equation solvefor x,z=1+(x-1)^2+4y^2 are x=sqrt(z-4y^2-1)+1,x=-sqrt(z-4y^2-1)+1
Find the zeros of solvefor x,z=1+(x-1)^2+4y^2
The zeros of solvefor x,z=1+(x-1)^2+4y^2 are x=sqrt(z-4y^2-1)+1,x=-sqrt(z-4y^2-1)+1