What are the solutions to the equation quadraticformula m^2-5m-14=0 ?

The solutions to the equation quadraticformula m^2-5m-14=0 are m=7,m=-2

Find the zeros of quadraticformula m^2-5m-14=0

The zeros of quadraticformula m^2-5m-14=0 are m=7,m=-2

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m^{2} - 5 m - 14 = 0

m = 7, m = - 2

Solution steps

m^{2} - 5 m - 14 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 14) = 9

m_{1, 2} = \frac{- ( - 5 ) \pm 9}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 5 ) + 9}{2 \cdot 1}, m_{2} = \frac{- ( - 5 ) - 9}{2 \cdot 1}

m = \frac{- ( - 5 ) + 9}{2 \cdot 1} : 7

m = \frac{- ( - 5 ) - 9}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

m = 7, m = - 2

- 10000 x^{2} + 4000 x + 9000 = 0

6 + 4 (4.5 - x) = 4 + x^{2}

2 x (2 x - 3) = 6 + x

13 x^{2} - 17 x + 7 = 0

\frac{x ^{2}}{9} - x + 2 = 0

What are the solutions to the equation quadraticformula m^2-5m-14=0 ?
The solutions to the equation quadraticformula m^2-5m-14=0 are m=7,m=-2
Find the zeros of quadraticformula m^2-5m-14=0
The zeros of quadraticformula m^2-5m-14=0 are m=7,m=-2