What are the solutions to the equation (t)=2t^2 ?

The solutions to the equation (t)=2t^2 are t= 1/2 ,t=0

Find the zeros of (t)=2t^2

The zeros of (t)=2t^2 are t= 1/2 ,t=0

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(t) = 2 t^{2}

t = \frac{1}{2}, t = 0

Decimal Notation

t = 0.5, t = 0

Solution steps

(t) = 2 t^{2}

Refine

t = 2 t^{2}

Switch sides

2 t^{2} = t

Move

t

to the left side

2 t^{2} - t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 \cdot 0 = 1

t_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 \cdot 2}

Separate the solutions

t_{1} = \frac{- ( - 1 ) + 1}{2 \cdot 2}, t_{2} = \frac{- ( - 1 ) - 1}{2 \cdot 2}

t = \frac{- ( - 1 ) + 1}{2 \cdot 2} : \frac{1}{2}

t = \frac{- ( - 1 ) - 1}{2 \cdot 2} : 0

The solutions to the quadratic equation are:

t = \frac{1}{2}, t = 0

p^{2} - 7 p = 18

x, y = 2 x^{2} + 1

3 y = y^{2} - 4

7 x^{2} - 5 = 58

1 2^{2} + 5^{2} = r^{2}

What are the solutions to the equation (t)=2t^2 ?
The solutions to the equation (t)=2t^2 are t= 1/2 ,t=0
Find the zeros of (t)=2t^2
The zeros of (t)=2t^2 are t= 1/2 ,t=0