What are the solutions to the equation 2x^2-4=10 ?

The solutions to the equation 2x^2-4=10 are x=sqrt(7),x=-sqrt(7)

Find the zeros of 2x^2-4=10

The zeros of 2x^2-4=10 are x=sqrt(7),x=-sqrt(7)

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2 x^{2} - 4 = 10

x = 7, x = - 7

Decimal Notation

x = 2.64575 \dots, x = - 2.64575 \dots

Solution steps

2 x^{2} - 4 = 10

Move

4

to the right side

2 x^{2} = 14

Divide both sides by

2

x^{2} = 7

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 7, x = - 7

5 v^{2} + 4 = - 9 v

x, f = (m - 2) x^{2} + (n - 1) x + (p - 3)

x^{2} + 10 x - 375 = 0

x, 6 x^{2} y + 11 x y - 2 x = 10 y

4 w^{2} + 8 w + 4 = 0

What are the solutions to the equation 2x^2-4=10 ?
The solutions to the equation 2x^2-4=10 are x=sqrt(7),x=-sqrt(7)
Find the zeros of 2x^2-4=10
The zeros of 2x^2-4=10 are x=sqrt(7),x=-sqrt(7)