What are the solutions to the equation x^2-12x+196=0 ?

The solutions to the equation x^2-12x+196=0 are x=6+4sqrt(10)i,x=6-4sqrt(10)i

Find the zeros of x^2-12x+196=0

The zeros of x^2-12x+196=0 are x=6+4sqrt(10)i,x=6-4sqrt(10)i

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x^{2} - 12 x + 196 = 0

x = 6 + 410 i, x = 6 - 410 i

Solution steps

x^{2} - 12 x + 196 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 196}{2 \cdot 1}

Simplify

(- 12)^{2} - 4 \cdot 1 \cdot 196 : 810 i

x_{1, 2} = \frac{- ( - 12 ) \pm 8 10 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 8 10 i}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 8 10 i}{2 \cdot 1}

x = \frac{- ( - 12 ) + 8 10 i}{2 \cdot 1} : 6 + 410 i

x = \frac{- ( - 12 ) - 8 10 i}{2 \cdot 1} : 6 - 410 i

The solutions to the quadratic equation are:

x = 6 + 410 i, x = 6 - 410 i

5 x^{2} - 12 x - 27 = 0

4 (x + 8)^{2} = 28

x, (λ^{2} - 9) x^{2} + (λ^{2} - 16) y^{2} = λ

- 5 m^{2} - 5 m - 56 = 0

3 x + x^{2} = 0

What are the solutions to the equation x^2-12x+196=0 ?
The solutions to the equation x^2-12x+196=0 are x=6+4sqrt(10)i,x=6-4sqrt(10)i
Find the zeros of x^2-12x+196=0
The zeros of x^2-12x+196=0 are x=6+4sqrt(10)i,x=6-4sqrt(10)i